Question
Solve equation using formula : $2x^2 – 3x – 1 = 0$

Answer

$\begin{aligned} & 2 x^2-3 x-1=0 \\ & \text { Here } a=2, b=-3, c=-1 \\ & D=b^2-4 a c \\ & =(-3)^2-4 \times 2 \times(-1) \\ & =9+8 \\ & =17 \\ & \because x=\frac{-b \pm \sqrt{D}}{2 a} \\ & =\frac{-(-3) \pm \sqrt{17}}{2 \times 2} \\ & =\frac{3 \pm \sqrt{17}}{4} \\ & \therefore x=\frac{3+\sqrt{17}}{4}, \frac{3-\sqrt{17}}{4} .\end{aligned}$

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