Question
Solve for ' $\theta$ ': $\cot ^2(\theta-5)^{\circ}=3$
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Answer
$ \cot ^2(\theta-5)^{\circ}=3$
$\Rightarrow \cot (\theta-5)^{\circ}=\sqrt{3}$
$\Rightarrow \cot (\theta-5)^{\circ}=\cot 30^{\circ}$
$\Rightarrow(\theta-5)^{\circ}=30^{\circ}$
$\Rightarrow \theta=30^{\circ}+5^{\circ}$
$\Rightarrow \theta=35^{\circ} .$
$\Rightarrow \cot (\theta-5)^{\circ}=\sqrt{3}$
$\Rightarrow \cot (\theta-5)^{\circ}=\cot 30^{\circ}$
$\Rightarrow(\theta-5)^{\circ}=30^{\circ}$
$\Rightarrow \theta=30^{\circ}+5^{\circ}$
$\Rightarrow \theta=35^{\circ} .$
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