MCQ
Solve for n in $4^n + 4^n + 4^n + 4^n = 2^{2010}$
- A$1005$
- B$2010$
- ✓$1004$
- D$1003$
✓
Answer
Correct option: C.
$1004$
Given, $4^n + 4^n + 4^n + 4^n = 2^{2010}$
$\Rightarrow 4 \times 4^n = 2^{2010}$
$\Rightarrow 2^{2n} = 2{2008}$
On equating, we get
$2^n = 2008$
$\Rightarrow n = 1004$
$\Rightarrow 4 \times 4^n = 2^{2010}$
$\Rightarrow 2^{2n} = 2{2008}$
On equating, we get
$2^n = 2008$
$\Rightarrow n = 1004$
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