Question
Solve for x:
2 tan-1(cos x) = tan-1 (2 cosec x).
2 tan-1(cos x) = tan-1 (2 cosec x).
$=\tan^{-1}\Bigg(\frac{\text{2 cos x}}{\text{sin}^{2}\text{x}}\Bigg)$
$\therefore\tan^{-1}\Bigg(\frac{\text{2 cos x}}{\text{sin}^{2}\text{ x}}\Bigg)=\tan^{-1}(2\text{ cosec x})$ $\Rightarrow\frac{2\cos\text{x}}{\sin^{2}\text{x}}=\frac{2}{\text{sin x}}\Rightarrow\sin\text{x}=\cos\text{x}$$\Rightarrow\text{x}=\pi/4.$
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