Question
Solve for $x : 2^{2x+1}= 8$

Answer

$2^{2 x+1}=8$
$\Rightarrow 2^{2 x+1}=2^3$
We know that if bases are equal, the powers are equal
$ \Rightarrow 2 x+1=3 $
$ \Rightarrow 2 x=3-1 $
$ \Rightarrow 2 x=2 $
$ \Rightarrow x=\frac{2}{2} $
$ \Rightarrow x=1$

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