Question
Solve for x and y:
2x + 3y = 0,
3x + 4y = 5
2x + 3y = 0,
3x + 4y = 5
✓
Answer
The given equation are:
2x + 3y = 0 ...(1)
3x + 4y = 5 ...(2)
On multiplying (1) by 4 and (2) by 3, we get:
8x + 12y = 0 ...(3)
9x + 12y = 15 ...(4)
On subtracting (3) and (4), we get:
x = 15
On substituting the value of x = 15 in (1), we get:
2 × 15 + 3y = 0
⇒ 3y = 0 - 30
⇒ 3y = -30 or y = -10
$\therefore$ x = 15 and y = -10
2x + 3y = 0 ...(1)
3x + 4y = 5 ...(2)
On multiplying (1) by 4 and (2) by 3, we get:
8x + 12y = 0 ...(3)
9x + 12y = 15 ...(4)
On subtracting (3) and (4), we get:
x = 15
On substituting the value of x = 15 in (1), we get:
2 × 15 + 3y = 0
⇒ 3y = 0 - 30
⇒ 3y = -30 or y = -10
$\therefore$ x = 15 and y = -10
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