Question
Solve for x and y:
$\text{2x}+\text{3y}+1=0,$
$\frac{7-\text{4x}}{3}=\text{y}$
$\text{2x}+\text{3y}+1=0,$
$\frac{7-\text{4x}}{3}=\text{y}$
✓
Answer
The given equations are: 7 - 4x = 3y -4x - 3y = -7 4x + 3y = 7 ...(1) 2x + 3y = -1 ...(2)Subtracting (2) from (1), we get
2x = 8
$\therefore$ x = 4
Substitution x = 4 in (1), we get
4 × 4 + 3y = 7
⇒ 3y = 7 - 16
⇒ 3y = -9
⇒ y = -3
$\therefore$ Solution is x = 4 and y = -3
2x = 8
$\therefore$ x = 4
Substitution x = 4 in (1), we get
4 × 4 + 3y = 7
⇒ 3y = 7 - 16
⇒ 3y = -9
⇒ y = -3
$\therefore$ Solution is x = 4 and y = -3
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