Question
Solve for x and y:
$\text{x}\begin{bmatrix}2\\1\end{bmatrix}+\text{y}\begin{bmatrix}3\\5\end{bmatrix}+\begin{bmatrix}-8\\-11\end{bmatrix}=0.$

Answer

We have, $\text{x}\begin{bmatrix}2\\1\end{bmatrix}+\text{y}\begin{bmatrix}3\\5\end{bmatrix}+\begin{bmatrix}-8\\-11\end{bmatrix}=0$

$\Rightarrow\ \begin{bmatrix}2\text{x}\\\text{x}\end{bmatrix}+\begin{bmatrix}3\text{y}\\5\text{y}\end{bmatrix}=\begin{bmatrix}-8\\-11\end{bmatrix}=0$

$\therefore\ \begin{bmatrix}2\text{x}+3\text{y}-8\\\text{x}+5\text{y}-11\end{bmatrix}=\begin{bmatrix}0\\0\end{bmatrix}$

$\Rightarrow\ 2\text{x}+3\text{y}-8=0\ ...(\text{i})$

and $\text{x}+5\text{y}-11=0\ ....(\text{ii})$

Solving equation (i) and (ii), we get

$\text{x}=1$ and $\text{y}=2$

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