Question
Solve for $x:2^{2x+1}= 8$
✓
Answer
$2^{2x+1}= 8$
$\Rightarrow 2^{2x+1}= 2^3$
$\Rightarrow 2x + 1 = 3$
$\Rightarrow 2x = 2$
$\Rightarrow x = 1.$
$\Rightarrow 2^{2x+1}= 2^3$
$\Rightarrow 2x + 1 = 3$
$\Rightarrow 2x = 2$
$\Rightarrow x = 1.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In $\triangle ABC,\text{AB} = \text{AC}.$ Show that the altitude $\text{AD}$ is median also.
→If $\theta = 30^\circ , $verify that$: \sin 3\theta = 4\sin\theta . \sin(60^\circ - \theta ) \sin(60^\circ + \theta )$
→In the figure, semiperimeter of triangle I is known. Would you be able to find the area of triangle II using Heron's formula?
If $\sin\theta = \cos\theta $ and $0^\circ < \theta <90^\circ $, find the value of $'\theta '.$
→Is it possible to have a polygon whose each interior angle is $105^\circ ?$
→Solve the equations:
x + 2y +9 = 0, 3x + 4y + 17 = 0
x + 2y +9 = 0, 3x + 4y + 17 = 0
If $A = 30^\circ ;$ show that:$ \cos 2A = \cos^4A - \sin^4A$
→If $\left(x^2+\frac{1}{x^2}\right)=7$, find the values of (i) $\left(x+\frac{1}{x}\right)$ (ii) $\left(x-\frac{1}{x}\right)$ (iii) $\left(2 x^2-\frac{2}{x^2}\right)$.
→Evaluate the following:$16^{\frac{3}{4}}+2\left(\frac{1}{2}\right)^{-1} \times 3^0$
→Without using table, find the value of the following: $\frac{\tan ^2 60^{\circ}+4 \cos ^2 45^{\circ}+3 \sec ^2 30^{\circ}+5 \cos 90^{\circ}}{\operatorname{cosec} 30^{\circ}+\sec 60^{\circ}-\cot ^2 30^{\circ}}$
→