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Factorization — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsFactorization3 Marks
Question
Solve:
$\frac{1}{16}\ \text{x}^2\text{y}^2-\frac{4}{49}\text{y}^2\text{z}^2$
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Answer

$\frac{1}{16}\ \text{x}^2\text{y}^2-\frac{4}{49}\text{y}^2\text{z}^2$
$=\text{x}^2\text{y}^2\Big(\frac{1}{16}\ \text{x}^2-\frac{4}{49}\ \text{z}^2\Big)$
$=\text{y}^2\Big[\Big(\frac{1}{4}\ \text{x}\Big)^2-\Big(\frac{2}{7}\ \text{z}\Big)^2\Big]$
$=\text{y}^2\Big(\frac{1}{4}\ \text{x}\ -\frac{2}{7}\ \text{z}\Big)\Big(\frac{1}{4}\ \text{x}+\frac{2}{7}\text{z}\Big){}$
$=\text{y}^2\ \Big(\frac{\text{x}}{4}-\frac{2}{7}\ \text{z}\Big)\Big(\frac{\text{x}}{4}+\frac{2}{7}\ \text{z}\Big)$

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