Question
Solve: $\frac{\mathrm{x}-4}{7}=\frac{\mathrm{x}+3}{7}+\frac{\mathrm{x}+4}{5}$
✓
Answer
$\begin{aligned} & \frac{\mathrm{x}-4}{7}=\frac{\mathrm{x}+3}{7}+\frac{\mathrm{x}+4}{5} \\ & \Rightarrow \frac{5 \mathrm{x}-20=5 x+15+7 x+28}{35} \\ & \Rightarrow 5 \mathrm{x}-5 \mathrm{x}-7 \mathrm{x}=15+28+20 \\ & \Rightarrow-7 \mathrm{x}=63 \\ & \Rightarrow \mathrm{x}=\frac{63}{-7}=-9 \\ & \therefore \mathrm{x}=-9\end{aligned}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify, giving Solution with positive index
$\frac{\left(5 x^7\right)^3 \cdot\left(10 x^2\right)^2}{\left(2 x^6\right)^7}=\frac{5^3 x^{7 \times 3} \cdot 10^2 \cdot x^{2 \times 2}}{2^7 \cdot x^{6 \times 7}}$
→$\frac{\left(5 x^7\right)^3 \cdot\left(10 x^2\right)^2}{\left(2 x^6\right)^7}=\frac{5^3 x^{7 \times 3} \cdot 10^2 \cdot x^{2 \times 2}}{2^7 \cdot x^{6 \times 7}}$
A rectangular lawn 115 m long and 64 m broad has two cross-paths at right-angles, one 2 m wide, running parallel to its length and the other 2.5 m wide, running parallel to its breadth. Find the cost of gravelling the paths at ₹ 114 per $m ^2$.
→Find the sum of: 9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 46x – 3
One kilogram of oil costs Rs. 73.40. Find the cost of 9.75 kilograms of oil.
Solve: 15 – 2 (5 - 3x) = 4 (x - 3) + 13
One side of a parallelogram is $20 cm$ and its distance from the opposite side is $16 cm $. Find the area of the parallelogram.
→Find the unknown marked angles in the given figure:
Evaluate: $48-[18-\{16-(5-\overline{4+1})\}]$
→If A = {even numbers less than 12},
B = {2, 4},
C = {1, 2, 3},
D = {2, 6} and E = {4} then
State if the following statement is true
C ⊆ A
B = {2, 4},
C = {1, 2, 3},
D = {2, 6} and E = {4} then
State if the following statement is true
C ⊆ A
The ratio between a base angle and the vertical angle of an isosceles triangle is 1: 4. Find each angle of the triangle.