Question
Solve: $\frac{x+1}{3}+\frac{x+4}{5}=\frac{x-4}{7}$

Answer


$\begin{aligned} & \frac{x+1}{3}+\frac{x+4}{5}=\frac{x-4}{7} \\ & \frac{x+1}{3}+\frac{x+4}{5}-\frac{x-4}{7}=0 \\ & \frac{35(x+1)+21(x+4)-15(x-4)}{105}=0 \\ & 35 x+35+21 x+84-15 x+60=0 \\ & 41 x+179=0 \\ & 41 x=-179 \\ & x=\frac{-179}{41} \\ & x=-4 \frac{15}{41}\end{aligned}$

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