Question
Solve graphically : 5y + 3 ≤ 0
i.e. $y=\frac{-3}{5}$
This represents a line parallel to $X$-axis passing through the point $\left(0, \frac{-3}{5}\right)$
Draw the line $y=\frac{-3}{5}$.
To find the solution set, we have to check the position of the origin (0, 0). When y = 0, 5y + 3 = 5 × 0 + 3 = 3 ≰ 0 ∴ the coordinates of the origin does not satisfy the given inequality.
$\therefore$ the solution set consists of the line $y=\frac{-3}{5}$ and the non-origin side of the line which is
shaded in the graph.

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| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(X) | $0$ | $k$ | $2k$ | $2k$ | $3k$ | $k^2$ | $2k^2$ | $7k^2 + k$ |

$\frac{4 e^x-25}{2 e^x-5}$