MCQ
Solve $\sqrt{3\text{x}^2}+\text{x}+\sqrt{3}=0$
- A$\frac{-1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
- B$\frac{1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
- C$\frac{1\pm\sqrt{11}}{6\sqrt{3}}$
- D$\frac{-1\pm\sqrt{11}}{6\sqrt{3}}$
✓
Answer
- $\frac{-1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
Solution:
$\sqrt{3\text{x}^2}+\text{x}+\sqrt{3}=0$
$\Rightarrow3\text{x}^2+\sqrt{3\text{x}}+3=0$
$\Rightarrow\text{D}=(\sqrt{3})^2-4.3.3=3-36=-33$
Since
$\text{D}\leq0,$ imaginary roots are there.Need a full question paper?
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