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Complex Numbers and Quadratic Equations — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsComplex Numbers and Quadratic Equations2 Marks
Question
Solve $\sqrt{5} x^{2}+x+\sqrt{5}=0$
✓

Answer

Here, a= $\sqrt 5$ = c and b = 1

the discriminant of the equation is
$1^{2}-4 \times \sqrt{5} \times \sqrt{5}=1-20=-19$
Therefore, the solutions are
= $\frac{-1 \pm \sqrt{-19}}{2 \sqrt{5}}=\frac{-1 \pm \sqrt{19} i}{2 \sqrt{5}}$

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