MCQ
Solve $\frac{\text{x}-1}{3}=\frac{\text{x}-2}{4}$:
- A$-2$
- B$2$
- C$10$
- ✓$-10$
$\frac{\text{x}-1}{3}=\frac{\text{x}-2}{4}$
$\Rightarrow 4(x + 1) = 3(x - 1)$
$\Rightarrow 4x + 4 = 3x - 6$
$\Rightarrow 4x - 3x = -6 - 4$
$\Rightarrow x = -10$
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