Question
Solve the differential equation $(x^2 – yx^2)dy + (y^2 + xy^2)dx = 0$

Answer

$\left( x ^2- y x ^2\right) d y +\left( y ^2+ xy y ^2\right) d x =0$
$\therefore x ^2(1- y ) d y + y ^2(1+ x ) d x =0$
$\therefore x ^2(1- y ) d y =- y ^2(1+ x ) d x$
$\therefore\left(\frac{1-y}{y^2}\right) d y=-\left(\frac{1+x}{x^2}\right) d x$
$\operatorname{lntegrating~on~both~sides,~we~get~}$
$\int\left(\frac{1-y}{y^2}\right) d y=-\int\left(\frac{1+x}{x^2}\right) d x$
$\therefore \int \frac{1}{y^2} d y-\int \frac{1}{y} d y=-\int \frac{1}{x^2} d x-\int \frac{1}{x} d x$
$\therefore \frac{y^{-1}}{-1}-\log |y|=\left(\frac{x^{-1}}{-1}\right)-\log |x|+ c$
$\therefore-\frac{1}{y}-\log |y|=\frac{1}{x}-\log |x|+ c$
$\therefore \log | x |-\log | y |=\frac{1}{x}+\frac{1}{y}+ c $

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