Question
Solve the equation: $2q + 6 = 0$
✓
Answer
The given equation is
$2q + 6 = 0$
Subtract 6 from both sides
$2q + 6 – 6 = 0 – 6$
$\therefore 2q = – 6$
Divide both sides by $2,$
$\frac{2 q}{2}=-\frac{6}{2}$
$\therefore q = – 3$
It is the required solution
$2q + 6 = 0$
Subtract 6 from both sides
$2q + 6 – 6 = 0 – 6$
$\therefore 2q = – 6$
Divide both sides by $2,$
$\frac{2 q}{2}=-\frac{6}{2}$
$\therefore q = – 3$
It is the required solution
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify:$24\div\frac{6}{7}$
→Solve the following equations. Check your result in case. $7 - 5x = 5 - 7x$
→Show that $36, 49, 6, 7$ are not in proportion.
→How much is $y^4-12 y^2+y+14$ greater than $17 y^3+34 y^2-51 y+68 ?$
→Solve the following.
In an isosceles triangle, the base angles are equal. The vertex angle is $40^{\circ}$. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is $180^{\circ}$ ).
→In an isosceles triangle, the base angles are equal. The vertex angle is $40^{\circ}$. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is $180^{\circ}$ ).
Write the given rational numbers in ascending order.$\frac{-1}{3}, \frac{-2}{9}, \frac{-4}{3}$
→For each solid, the three views (i), (ii) and (iii) are given. Identify for each solid the corresponding top, front and side views.
Express $\frac{14}{-5}$ as a rational number with numerator $56$
→Divide: $\frac{3}{10}$ by $\big(\frac{1}{4}\ \text{of}\ \frac{3}{5}\big)$
→If p = - 2 then find the value of
$-2 p^3-3 p^2+4 p+7$
→$-2 p^3-3 p^2+4 p+7$