Question
Solve the equation $2y - 1 = y + 1$ and represent it graphically on the coordinate plane.
✓
Answer
We are given,
$2y - 1 = y + 1$
we get,
$2y - y = 1 + 1$
$y = 2$
The representation of the solution on the Cartesian plane, it is a line parallel to y axis passing through the point $(0, 2)$ is shown below
$2y - 1 = y + 1$
we get,
$2y - y = 1 + 1$
$y = 2$
The representation of the solution on the Cartesian plane, it is a line parallel to y axis passing through the point $(0, 2)$ is shown below
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
It being given that $\sqrt{2}=1.414,\sqrt{3}=1.732,\sqrt{5}=2.236$ and $\sqrt{10}=3.162,$ find the value of three places of decimals, of the following:
$\frac{2}{\sqrt{5}}$
→$\frac{2}{\sqrt{5}}$
Express the following decimals in the form $\frac{\text{p}}{\text{q}},$ where $p, q$ are integers and $\text{q}\neq0.$ $0.\overline{2}$
→Locate $\sqrt{5}$ on the number line.
→Factorize the following expressions:
$8 x^3-125 y^3+180 x y+216$
→$8 x^3-125 y^3+180 x y+216$
Evaluate: $\big[(16)^{\frac{1}{2}}\big]^{\frac{1}{2}}$
→In an isosceles triangle $ABC$ , with $AB = AC$, the bisectors of $\angle B$ and $\angle C$ intersect each other at $O$ . Join A to $O$ . Show that $O B=O C$ and $A O$ bisects $\angle A$.
→Give the geometric representations of the following equations:
$a.$ On the number line.
$b.$ On the Cartesain plane.
$y = 3$
→$a.$ On the number line.
$b.$ On the Cartesain plane.
$y = 3$
In Fig., if $AB \| DE$ and $BD \| FG$ such that $\angle FGH =125^{\circ}$ and $\angle B =55^{\circ},$ find $x$ and $y$ .
→ Solve the following equations:
$4^{2\text{x}}=(\sqrt[3]{16})^{\frac{-6}{\text{y}}}=(\sqrt{8})^2$
→$4^{2\text{x}}=(\sqrt[3]{16})^{\frac{-6}{\text{y}}}=(\sqrt{8})^2$
If $x = 3$ and $y = -1$, find the values of the following using in identity:
$\Big(\frac{\text{x}}{7}+\frac{\text{y}}{3}\Big)\Big(\frac{\text{x}^2}{49}+\frac{\text{y}^2}{9}-\frac{\text{xy}}{21}\Big)$
→$\Big(\frac{\text{x}}{7}+\frac{\text{y}}{3}\Big)\Big(\frac{\text{x}^2}{49}+\frac{\text{y}^2}{9}-\frac{\text{xy}}{21}\Big)$