Question
Solve the equations:
$\frac{a}{x}-\frac{b}{y}=0, \frac{a b^2}{x}+\frac{a^2 b}{y}=\left(a^2+b^2\right)$
$\frac{a}{x}-\frac{b}{y}=0, \frac{a b^2}{x}+\frac{a^2 b}{y}=\left(a^2+b^2\right)$
✓
Answer
x = a, y = b
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