Question
Solve the equations:
$\frac{x}{7}+\frac{y}{3}=5, \frac{x}{2}-\frac{y}{9}=6$
$\frac{x}{7}+\frac{y}{3}=5, \frac{x}{2}-\frac{y}{9}=6$
✓
Answer
x = 14, y = 9
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the given figure, $\angle ABC =66^{\circ}, \angle DAC =38^{\circ}$. CE is perpendicular to $A B$ and $A D$ is perpendicular to $B C$. Prove that: $CP > AP$
→Solve the following equations for the unknown: $\frac{5}{3 x-2}-\frac{1}{8}=0, x \neq 0, x \neq \frac{2}{3}$
→
In an equilateral triangle $\Delta$ABC of side 14 cm, side BC is the diameter of a semi-circle as shown in the figure. Find the area of the shaded region.
(Take $\pi=\frac{22}{7}$ and $\sqrt{3}=1.732$ )
[Hint : Required Area
= (Area of equilateral $\Delta$ABC )+ (Area of semi-circle BDC)
$=\left[\left(\frac{\sqrt{3}}{4} \times 14 \times 14\right)+\left(\frac{1}{2} \pi \times 7 \times 7\right)\right] cm ^2$
Insert five irrational number's between $2 \sqrt{3}$ and $3 \sqrt{5}$.
→Express $\left(x^2+8 x-15\right)\left(x^2-8 x-15\right)$ as the difference of two squares.
→In the given figure, ABCD is a square of side 14 cm and A, B, C, D are centres of circular arcs, each of radius 7 cm. Find the area of the shaded region.
Find the value of: $\log _8 2$
→Find the area enclosed between two concentric circles of radii $6.3\ cm$ and $ 8.4\ cm$. A third concentric circle is drawn outside the $8.4\ cm$ circle. So that the area enclosed between it and the $8.4\ cm$ circle is the same as that between the two inner circles. Find the radii of the third circle correct to two decimal places.
→The diameters of three circles are in the ratio $3: 5: 6$. If the sum of the circumferences of these circles is $308 \ cm$; find the difference between the areas of the largest and the smallest of these circles.
→Solve the following equations for the unknown: $7-\frac{1}{\sqrt{y}}=0$
→