MCQ
Solve the following differential equation. $\frac{\text{dy}}{\text{dx}}=\text{x}-1$
  • A
    $ y=x^2+x $
  • B
    $ y=x^2 $
  • $ y=x^2-x $
  • D
    None of the above

Answer

Correct option: C.
$ y=x^2-x $
Given, $\frac{\text{dy}}{\text{dx}}=\text{x}-1$
Integrating on both sides
$\int\frac{\text{dy}}{\text{dx}}=\int\text{x}-1\text{ dx}$
$y = x^2- x + c$

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