Question
Solve the following differential equations : $d y+(2 y) d x=8 d x$

Answer

$dy +(2 y ) dx =8 dx$
$\therefore \frac{d y}{d x}+2 y =8$
This is the linear differential equation of the form
$ \frac{d y}{d x}+P y=Q, \text { where } P=2, Q=8$
$\therefore \text { I.F. } =e^{\int P d x}=e^{2 \int d x}=e^{2 x}$
$ \therefore \text { the solution } f(1) \text { is given by }$
$ y \cdot \text { (I.F.) }=\int Q(\text { I.F.) } d x+c$
$ \therefore y e^{2 x}=\int 8 e^{2 x} d x+c$
$ \quad=8\left(\frac{e^{2 x}}{2}\right)+c$
$ \therefore y e^{2 x}=4 e^{2 x}+c$
This is the general solution.

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