Question
Solve the following differential equations:
$\frac{\text{dy}}{\text{dx}}=(\cos^2\text{x}-\sin^2\text{x})\cos^2\text{y}$
$\frac{\text{dy}}{\text{dx}}=(\cos^2\text{x}-\sin^2\text{x})\cos^2\text{y}$
✓
Answer
$\frac{\text{dy}}{\text{dx}}=(\cos^2\text{x}-\sin^2\text{x})\cos^2\text{y}$
$\frac{\text{dy}}{\cos^2\text{y}}=(\cos^2\text{x}-\sin^2\text{x})\text{dx}$
$\int\sec^2\text{y dy}=\int\cos2\text{x dx}$
$\tan\text{y}=\frac{\sin2\text{x}}{2}+\text{C}$
$\frac{\text{dy}}{\cos^2\text{y}}=(\cos^2\text{x}-\sin^2\text{x})\text{dx}$
$\int\sec^2\text{y dy}=\int\cos2\text{x dx}$
$\tan\text{y}=\frac{\sin2\text{x}}{2}+\text{C}$
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