Question
Solve the following differential equations:
$\text{x}^2\text{dy}+\text{y}(\text{x + y})\text{dx}=0$

Answer

We have,
$\text{x}^2\text{dy}+\text{y}(\text{x + y})\text{dx}=0$
$\Rightarrow\ \text{x}^2\text{dy}=-\text{y}(\text{x + y})\text{dx}$
$\Rightarrow\ \frac{\text{dy}}{\text{dx}}=\frac{-\text{y}(\text{x + y})}{\text{x}^2}$
This is a homogeneous differential equation.
Putting y = vx and $\frac{\text{dy}}{\text{dx}}=\text{v + x}\frac{\text{dv}}{\text{dx}}$, we get
$\text{v + x}\frac{\text{dv}}{\text{dx}}=\frac{-\text{vx}(\text{x + vx})}{\text{x}^2}$
$\Rightarrow\ \text{v + x}\frac{\text{dv}}{\text{dx}}=-\text{v}(1+\text{v})$
$\Rightarrow\ \text{x}\frac{\text{dv}}{\text{dx}}=-\text{v}-\text{v}-\text{v}^2$
$\Rightarrow\ \text{x}\frac{\text{dv}}{\text{dx}}=-(\text{v}^2+2\text{v})$
$\Rightarrow\ \frac{\text{dv}}{(\text{v}^2+2\text{v})}=-\frac{\text{dx}}{\text{x}}$
$\Rightarrow\ \frac{\text{dv}}{\text{v}(\text{v}+2)}=-\frac{\text{dx}}{\text{x}}$
Integrating both sides, we get
$\int\frac{\text{dv}}{\text{v}(\text{v}+2)}=-\int\frac{\text{dx}}{\text{x}}$
$\Rightarrow\ \frac{1}2\int\Big[\frac{1}{\text{v}}-\frac{1}{\text{v}+2}\Big]\text{dv}=-\int\frac{\text{dx}}{\text{x}}$
$\Rightarrow\ \frac{1}2\Big[\int\frac{1}{\text{v}}\text{dv}-\int\frac{1}{\text{v}+2}\text{dv}\Big]=-\int\frac{\text{dx}}{\text{x}}$
$\Rightarrow\ \frac{1}2\big[\log|\text{v}|-\log|\text{v}+2|\big]=-\log|\text{x}|+\log\text{C}$
$\Rightarrow\ \frac{1}2\log\Big|\frac{\text{v}}{\text{v}+2}\Big|=\log\Big|\frac{\text{C}}{\text{x}}\Big|$
$\Rightarrow\ \log\Big|\frac{\text{v}}{\text{v}+2}\Big|=\log\Big|\frac{\text{C}^2}{\text{x}^2}\Big|$
$\Rightarrow\ \frac{\text{v}}{\text{v}+2}=\frac{\text{C}^2}{\text{x}^2}$
$\Rightarrow\ \frac{\frac{\text{y}}{\text{x}}}{\frac{\text{y}}{\text{x}}+2}=\frac{\text{C}^2}{\text{x}^2}$
$\Rightarrow\ \frac{\text{y}}{\text{y}+2\text{x}}=\frac{\text{C}^2}{\text{x}^2}$
$\Rightarrow\ \text{x}^2\text{y}=\text{C}^2(\text{y +2x})$
$\Rightarrow\ \text{x}^2\text{y}=\text{K}(\text{y +2x})$ (Where, $K = C^2$)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Find the equation of the plane that is perpendicular to the plane $5x + 3y + 6z + 8 = 0$ and which contains the line of intersection of the planes $x + 2y + 3z - 4 = 0, 2x + y - z + 5 = 0$.
Solve the following equation:
$\text{x}\frac{\text{dy}}{\text{dx}}+\text{y}=\text{y}^2$
Show that the relative error in computing the volume of a sphere, due to an error in measuring the radius, is approximately equal to three times the relative error in the radius.
Find the angle between the following pairs of lines:$\frac{\text{x}-5}{1}=\frac{2\text{y}+6}{-2}=\frac{\text{z}-3}{1}$ and $\frac{\text{x}-2}{3}=\frac{\text{y}+1}{4}=\frac{\text{z}-6}{5}$
Solve the following systems of linear equations by cramer's rule:
9x + 5y = 10,
3x - 2y = 8
Find the distance of the point (1, -5, 9) from the plane x - y + z = 5 measured along the line x = y = z.
$\triangle O A B$ is formed by lines $x^2-4 x y+y^2=0$ and the line $2 x+3 y-1=0$. Find the equation of the median of the triangle drawn from $\mathrm{O}$.
A farmer mixes two brands P and Q of cattle feed. Brand P, costing Rs. 250 per bag, contains 3 units of nutritional element A, 2.5 units of element B and 2 units of element C. Brand Q costing Rs. 200 per bag contains 1.5 units of nutritional element A, 11.25 units of element B and 3 units of element C. The minimum requirements of nutrients A, B and C are 18 units, 45 units and 24 units respectively. Determine the number of bags of each brand which should be mixed in order to produce a mixture having a minimum cost per bag? What is the minimum cost of the mixture per bag?
Find $\frac{\text{dy}}{\text{dx}},$ when
$\text{x}=\text{e}^{\theta}\Big(\theta+\frac{1}{\theta}\Big)\text{ and y}=\text{e}^{-\theta}\Big(\theta-\frac{1}{\theta}\Big)$
If O be the origin and the coordinates of P be (1, 2, -3), then find the equation of the plane passing through P and perpendicular to OP.