Differential Equation and Applications (p-1) — Maths (commerce) STD 12 Commerce / Arts — Question
Maharashtra BoardEnglish MediumSTD 12 Commerce / ArtsMaths (commerce)Differential Equation and Applications (p-1)1 Mark
Question
Solve the following differential equations : $x d x+2 y d y=0$
✓
Answer
$ x d x+2 y d y=0 $ Integrating, we get $ \begin{aligned} & \int xdx +2 \int ydy = c _1 \\ & \therefore \frac{x^2}{2}+2\left(\frac{y^2}{2}\right)=c_1 \\ & \therefore x ^2+2 y ^2=c_{\text {, }} \text { where } c =2 c _1 \end{aligned} $ This is the general solution.
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