Question
Solve the following differential equations.
$y-x \frac{d y}{d x}=0$
$y-x \frac{d y}{d x}=0$
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The square of any even number is odd or the cube of any odd number is odd.
$xy =\log y + c _{;} \frac{d y}{d x}=\frac{y^2}{1-x y}$