Question
Solve the following equation: $2x^2 - x - 6 = 0$

Answer

$2 x^2-x-6=0 $
$x^2-\frac{1}{2} x-3=0$
$x^2-2 x+\frac{3}{2} x-3=0 $
$ x(x-2)+\frac{3}{2}(x-2)=0$
$(x-2)\left(x+\frac{3}{2}\right)=0 $
$ (x-2)=0,\left(x+\frac{3}{2}\right)=0$
$x=2, x=-\frac{3}{2}$

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