Question
Solve the following equation: $4x^2 - 13x - 12 = 0$

Answer

$4 x^2-13 x-12=0$
$x^2-\frac{13}{4} x-3=0$
$x^2-4 x+\frac{3}{4} x-3=0$
$ x(x-4)+\frac{3}{4}(x-4)=0$
$(x-4)\left(x+\frac{3}{4}\right)=0$
$ (x-4)=0,\left(x+\frac{3}{4}\right)=0$
$x=4, x=-\frac{3}{4}$

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