Solve the following equation: 4x^2 + 16x = 0 - Vidyadip

Question

Solve the following equation: $4x^2 + 16x = 0$

✓

Answer

$4x^2 + 16x = 0$
$4x(x + 4) =0$
$4x = 0, (x + 4) =0$
$x = 0, x = - 4$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "[2 Mark Question Answer]" from Quadratic Equations→Quadratic Equations — all question types→Mathematics STD 10 question papers→ICSE Board STD 10 question papers→ICSE Board question paper generator→

Similar questions

In a single throw of die, find the probability of getting: 5

4 defective pens are accidentally mixed with 16 good ones. It is not possible to just look at a pen and tell whether or not it is defective. One pen is drawn at random from the lot. What is the probability that the pen is defective?

Prove the following identities: $\sec^2\theta + cosec^2\theta = \sec^2\theta\ cosec^2\theta $.

The mean of the number 6, ‘y’, 7, ‘x’ and 14 is 8. Express ‘y’ in terms of ‘x’.

If $x: y = 4: 7,$ find the value of $(3x + 2y): (5x + y).$

$
\text { Prove that } \frac{\sin A}{\sin \left(90^{\circ}-A\right)}+\frac{\cos A}{\cos \left(90^{\circ}-A\right)}=\sec \left(90^{\circ}-A\right) \cos e c\left(90^{\circ}-A\right)
$

If $A=\left[\begin{array}{ll}2 & x \\ 0 & 1\end{array}\right]$ and $B=\left[\begin{array}{cc}4 & 36 \\ 0 & 1\end{array}\right]$, find the value of $x$, given that $A^2-B$

Draw and describe the lorus in the following cases:
The locus of points at a distance of 4 cm from a fixed line.

Prove the following identitie:$1-\frac{\sin ^2 A}{1+\cos A}=\cos A$

l is the perpendicular bisector of line segment PQ and R is a point on the same side of l as P. The segment QR intersects l at X. Prove that PX + XR = QR.