Question
Solve the following equation: $abx^2 +(b^2-ac) x - bc = 0$
✓
Answer
$a b x^2+\left(b^2-a c\right) x-b c=0$
$a b x^2+b^2 x-a c x-b c=0 $
$ b x(a x+b)-c(a x+b)=0 $
$ (a x+b)(b x-c)=0 $
$ x=-\frac{b}{a}, x=\frac{c}{b}$
$a b x^2+b^2 x-a c x-b c=0 $
$ b x(a x+b)-c(a x+b)=0 $
$ (a x+b)(b x-c)=0 $
$ x=-\frac{b}{a}, x=\frac{c}{b}$
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