Question
Solve the following equation and verify the answer: $3(x + 6) + 2(x + 3) = 64$

Answer

$3(x + 6) + 2 (x + 3) = 64 $
$\Rightarrow 3x + 18 + 2x + 6 = 64$ (Removing brackets) 
$\Rightarrow 3x + 2x + 18 + 6 = 64 $
$\Rightarrow 5x + 24 = 64 $
$\Rightarrow 5x = 64 - 24$ (Transposing $24$ to $R.H.S.) $
$\Rightarrow 5x = 40$
$\Rightarrow\frac{\text{5x}}{5}=\frac{40}{5}$(Dividing both sides by $5)$
$\Rightarrow x = 8$
So, $x = 8$ is a solution of the given equation.
Check: Substituting $x = 8$ in the given equation,
we get $L.H.S. = 3(8 + 6) + 2(8 + 3) = 3 \times 14 + 2 \times 11 = 42 + 22 = 64 = R.H.S.$
$\therefore$ When $x = 8$, we have $L.H.S. = R.H.S$

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