Question
Solve the following equation and verify the answer:
5(x - 1) + 2(x + 3) + 6 = 0
5(x - 1) + 2(x + 3) + 6 = 0
✓
Answer
5(x - 1) + 2(x + 3) + 6 = 0 ⇒ 5(x - 1) + 2(x + 3) = -6 (Transposing 6 to R.H.S.) ⇒ 5x - 5 + 2x + 6 = -6 (Removing brackets) ⇒ 5x + 2x - 5 + 6 = -6 ⇒ 7x + 1 = -6 ⇒ 7x = -6 - 1 (Transposing 1 to R.H.S.) ⇒ 7x = -7 $\Rightarrow\frac{\text{7x}}{7}=\frac{-7}{7}$(Dividing both sides by 7)
⇒ x = -1 So, x = -1 is a solution of the given equation. Check: Substituting x = -1 in the given equation, we get L.H.S. = 5(-1 - 1) + 2(-1 + 3) + 6 = 5 × (-2) + 2 × 2 + 6 = 10+ 4 +6 = -10 + 10 = 0 = R.H.S.$\therefore$ When x = -1, we have
L.H.S. = R.H.S.
⇒ x = -1 So, x = -1 is a solution of the given equation. Check: Substituting x = -1 in the given equation, we get L.H.S. = 5(-1 - 1) + 2(-1 + 3) + 6 = 5 × (-2) + 2 × 2 + 6 = 10+ 4 +6 = -10 + 10 = 0 = R.H.S.$\therefore$ When x = -1, we have
L.H.S. = R.H.S.
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