Question
Solve the following equation : $ax ^2+\left(4 a ^2-3 b \right) x -12 ab =0$
✓
Answer
$a x^2+\left(4 a^2-3 b\right) x-12 a b=0 $
$x^2+4 a x-3 \frac{b}{a} x-12 b=0 $
$ x(x+4 a)-3 \frac{b}{a}(x+4 a)=0 $
$ (x+4 a)\left(x-3 \frac{b}{a}\right)=0 $
$ x=-4 a, x=3 \frac{b}{a}$
$x^2+4 a x-3 \frac{b}{a} x-12 b=0 $
$ x(x+4 a)-3 \frac{b}{a}(x+4 a)=0 $
$ (x+4 a)\left(x-3 \frac{b}{a}\right)=0 $
$ x=-4 a, x=3 \frac{b}{a}$
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