Question
Solve the following equation by trial and error method: $\frac{1}{2}\text{x}+7=11$
✓
Answer
The given equation is $\frac{1}{2}\text{x}+7=11$ We guess and try several values of $x$ to find $L.H.S$. and $R.H.S.$ and stop when $L.H.S. = R.H.S.$
When $x = 8$, we have $L.H.S. = R.H.S$
So, $x = 8$ is the solution of the given equation.
| x | L.H.S. | R.H.S. |
| $2$ | $\frac{1}{2}\times2+7=8$ | $11$ |
| $4$ | $\frac{1}{2}\times4+7=9$ | $11$ |
| $6$ | $\frac{1}{2}\times6+7=10$ | $11$ |
| $8$ | $\frac{1}{2}\times8+7=$11$$ | $11$ |
So, $x = 8$ is the solution of the given equation.
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