Question
Solve the following equation by trial and error method:
$\frac{\text{x}}{3}=4$

Answer

The given equation is $\frac{\text{x}}{3}=4$
We guess and try several values of $x$ to find $L.H.S.$ and $R.H.S$. and stop when $L.H.S. = R.H.S.$​​​​​​​
x L.H.S. R.H.S.
$3$ $\frac{3}{3}=1$ $4$
$6$ $\frac{6}{3}=2$ $4$
$9$ $\frac{9}{3}=3$ $4$
$12$ $\frac{12}{3}=4$ $4$
When $x = 12,$
we have $L.H.S. = R.H.S$
So $x = 12$ is the solution of the given equation.

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