Question
Solve the following equation by trial and error method: $z - 3 = 2z - 5$

Answer

The given equation is $z - 3 = 2z - 5$ We guess and try several values of z to find $L.H.S.$ and $R.H.S.$ and stop when $L.H.S. = R.H.S.$
x
L.H.S.
R.H.S.
$1$
$1 - 3 = -2$
$2 \times 1 - 5 = -3$
$2$
$2 - 3 = -1$
$2 \times 2 - 5 = -1$
When $z = 2$, we have $L.H.S. = R.H.S$ So, $z = 2$ is the solution of the given equation.

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