Question
Solve the following equation by trial and error method: $z - 3 = 2z - 5$
|
x
|
L.H.S.
|
R.H.S.
|
|
$1$
|
$1 - 3 = -2$
|
$2 \times 1 - 5 = -3$
|
|
$2$
|
$2 - 3 = -1$
|
$2 \times 2 - 5 = -1$
|
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
