Question
Solve the following equation: c
✓
Answer
$\frac{2}{x^2}-\frac{5}{x}+2=0$
$ 2-5 x+2 x^2=0$
$ 2 x^2-5 x+2=0$
$x^2-\frac{5}{2} x +1=0 $
$ x ^2-2 x-\frac{1}{2} x +1=0 $
$x ( x -2)-\frac{1}{2}( x -2)=0$
$ ( x -2)\left( x -\frac{1}{2}\right)=0 $
$ ( x -2)=0,\left( x -\frac{1}{2}\right)=0 $
$ x =2, x =\frac{1}{2}$
$ 2-5 x+2 x^2=0$
$ 2 x^2-5 x+2=0$
$x^2-\frac{5}{2} x +1=0 $
$ x ^2-2 x-\frac{1}{2} x +1=0 $
$x ( x -2)-\frac{1}{2}( x -2)=0$
$ ( x -2)\left( x -\frac{1}{2}\right)=0 $
$ ( x -2)=0,\left( x -\frac{1}{2}\right)=0 $
$ x =2, x =\frac{1}{2}$
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