Question
Solve the following equation for$ A,$ if $\sin 3 A =\frac{\sqrt{3}}{2}$

Answer

$\sin 3 A=\frac{\sqrt{3}}{2} $
$ \sin 3 A=\sin 60^{\circ} $
$ 3 A=60^{\circ} A=20^{\circ}$

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