Question
Solve the following equation: $x^2-(\sqrt{2}+1) x+\sqrt{2}=0$

Answer

$x^2-(\sqrt{2}+1) x+\sqrt{2}=0 $
$x^2-x-\sqrt{2} x+\sqrt{2}=0$
$ x(x-1)-\sqrt{2}(x-1)=0 $
$ (x-1)(x-\sqrt{2})=0 $
$(x-1)=0,(x-\sqrt{2})=0 $
$ x=1, x=\sqrt{2}$

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