Question
Solve the following equations :

$3(y+8)=10(y-4)+8$

Answer

$
\begin{aligned}
& \text {} 3(y+8)=10(y-4)+8 \\
& \therefore 3 y+24=10 y-40+8 \\
& \therefore 3 y+24=10 y-32 \\
& \therefore 3 y+24-24=10 y-32-24
\end{aligned}
$
...[Subtracting 24 from both the sides]
$
\begin{aligned}
& \therefore 3 y=10 y-56 \\
& \therefore 3 y-10 y=10 y-56
\end{aligned}
$
...[Subtracting 10y from both the sides]
$
\begin{aligned}
& \therefore-7 y=-56 \\
& \therefore \frac{-7 y}{-7}=\frac{-56}{-7} \ldots \text { [Dividing both the sides by }-7 \text { ] } \\
& \therefore y=8
\end{aligned}
$

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