Question
Solve the following equations by trial and error method: $\frac{15}{\text{x}}=3$
✓
Answer
$\frac{15}{\text{x}}=3$ Here, $\text{L.H.S.}=\frac{15}{\text{x}}$ and $R.H.S. = 3$.
Since $R.H.S.$ is a natural number, $\frac{15}{\text{x}}$ must also be a natural number,
so we must substitute values of $x$ that are factors of $15$.
Therefore, if $x = 5, L.H.S. = R.H.S.$ Hence, $x = 5$ is the solution to this equation.
Since $R.H.S.$ is a natural number, $\frac{15}{\text{x}}$ must also be a natural number,
so we must substitute values of $x$ that are factors of $15$.
| x | L.H.S. | R.H.S. | Is L.H.S. = R.H.S. |
| $1$ | $\frac{15}{1}=15$ | $3$ | No |
| $3$ | $\frac{15}{3}=5$ | $3$ | No |
| $5$ | $\frac{15}{5}=3$ | $3$ | Yes |
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