Question
Solve the following equations by trial and error method:
$\frac{15}{\text{x}}=3$

Answer

$\frac{15}{\text{x}}=3$ Here, $\text{L.H.S.}=\frac{15}{\text{x}}$ and R.H.S. = 3.
Since R.H.S. is a natural number, $\frac{15}{\text{x}}$ must also be a natural number, so we must substitute values of x that are factors of 15.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.
$1$ $\frac{15}{1}=15$ $3$ No
$3$ $\frac{15}{3}=5$ $3$ No
$5$ $\frac{15}{5}=3$ $3$ Yes
Therefore, if x = 5, L.H.S. = R.H.S.
Hence, x = 5 is the solution to this equation.

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