Solve the following equations by trial and error method. 5 p+2=17 - Vidyadip

Question

Solve the following equations by trial and error method.
$5 p+2=17$

✓

Answer

Given equation is $5 p+2=17$.
When $p=0$, then LHS $=5 \times 0+2=0+2=2$
and$\qquad$RHS $=17$
$\therefore$$\qquad$ LHS $\neq$ RHS
$\begin{array}{l}\text {When } p=1 \text {, then LHS }=5 \times 1+2=5+2=7 \\\text {and } \qquad \text { RHS }=17 \\ \begin{array}{ll}\therefore\text { LHS } \neq \text { RHS }\end{array}\end{array}$
$\begin{array}{l}\text {When } p=2 \text {, then LHS }=5 \times 2+2=10+2=12 \\ \text {and }\qquad \text { RHS }=17 \\ \therefore \text { LHS } \neq \text { RHS } \\ \text {When } p=3 \text {, then LHS }=5 \times 3+2=15+2=17\end{array}$
$
\therefore\text { LHS }=\text { RHS }
$
So, $p=3$ is the solution of the given equation.

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