Question
Solve the following equations by trial and error method.
$6 m+2=14$
$6 m+2=14$
✓
Answer
Given, $6 m+2=14$
On putting $m=0$ in $6 m+2=14$, we get
$(6 \times 0)+2=14$
$\Rightarrow
0+2=14$
$\Rightarrow
2 \neq 14$
Now, on putting m =1 in 6m + 2 =14, we get
$(6 \times 1)+2=14$
$\Rightarrow
6+2=14$
$\Rightarrow \quad 8 \neq 14$
Again, on putting m = 2 in 6m + 2 =14, we get
(6 x 2) +2=14
$\Rightarrow\qquad$ 12+2=14
$\Rightarrow\qquad$14=14
So, m = 2 is the solution of the given equation 6m+2=14.
On putting $m=0$ in $6 m+2=14$, we get
$(6 \times 0)+2=14$
$\Rightarrow
0+2=14$
$\Rightarrow
2 \neq 14$
Now, on putting m =1 in 6m + 2 =14, we get
$(6 \times 1)+2=14$
$\Rightarrow
6+2=14$
$\Rightarrow \quad 8 \neq 14$
Again, on putting m = 2 in 6m + 2 =14, we get
(6 x 2) +2=14
$\Rightarrow\qquad$ 12+2=14
$\Rightarrow\qquad$14=14
So, m = 2 is the solution of the given equation 6m+2=14.
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