Question
Solve the following equations by trial and error method.
$7 P+6=27$
$7 P+6=27$
✓
Answer
Given, 7 P + 6=27
On putting P=0 in7P+6 = 27, we get
(7×0)+6= 27
$\Rightarrow
0+6=27 \Rightarrow 6 \neq 27$
Now, on putting P=1 in 7P+6 = 27, we get
(7×1)+6=27
$\Rightarrow
7+6=27 \Rightarrow 13 \neq 27$
Again, on putting P = 2 in 7P+6 = 27, we get
(7 x 2) +6 = 27
$\Rightarrow 14 + 6=27 \Rightarrow 20 \neq 27$
Again, on putting P = 3 in 7P +6 = 27, we get
(7x3) +6= 27
$\Rightarrow 21+6=27 \Rightarrow 27=27$
Hence, P = 3 is the solution of given equation 7p+6=27.
On putting P=0 in7P+6 = 27, we get
(7×0)+6= 27
$\Rightarrow
0+6=27 \Rightarrow 6 \neq 27$
Now, on putting P=1 in 7P+6 = 27, we get
(7×1)+6=27
$\Rightarrow
7+6=27 \Rightarrow 13 \neq 27$
Again, on putting P = 2 in 7P+6 = 27, we get
(7 x 2) +6 = 27
$\Rightarrow 14 + 6=27 \Rightarrow 20 \neq 27$
Again, on putting P = 3 in 7P +6 = 27, we get
(7x3) +6= 27
$\Rightarrow 21+6=27 \Rightarrow 27=27$
Hence, P = 3 is the solution of given equation 7p+6=27.
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