Question
Solve the following equations by using the method of completing the square:
$5x^2 - 6x - 2 = 0$

Answer

$5x^2 - 6x - 2 = 0 $
$\Rightarrow 25x^2 - 30x - 10 = 0$ (Multiplying both sides by $5$)
$\Rightarrow 25x^2 - 30x = 10 $
$\Rightarrow (5x)^2 - 2 \times 5x \times 3 + 3^2 = 10 + 3^2$ [Adding $3^2$​​​​​​​ on both sides]
$\Rightarrow (5x - 3)^2 = 10 + 9 = 19$
$\Rightarrow\text{5x}-3=\pm19$ (Taking square root on both sides)
$\Rightarrow\text{5x}-3=\sqrt{19}$ or $\text{5x}- 3=-\sqrt{19}$
$\Rightarrow\text{5x}=3+\sqrt{19}$ or $\text{5x}=3-\sqrt{19}$
$\Rightarrow\text{x}=\frac{3+\sqrt{19}}{5}$ or $\text{x}=\frac{3-\sqrt{19}}{5}$
Hence, $\frac{3+\sqrt{19}}{5}$ and $\frac{3-\sqrt{19}}{5}$ are the roots of the given equation.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Solve the following system of equations by the method of cross-multiplication:
3x + 2y + 25 = 0,
2x + y + 10 = 0.
Solve the following simultaneous equation.
$\frac{10}{x+y}+\frac{2}{x-y}=4 ; \frac{15}{x+y}-\frac{5}{x-y}=-2$
₹ 1000 is invested at 10 percent simple interest. Check at the end of every year if the total interest amount is in A.P. If this is an A.P. then find interest amount after 20 years. For this complete the following activity.
$\text { Simple interest }=\frac{P \times R \times N}{100}$
Simple interest after 1 year $=\frac{1000 \times 10 \times 1}{100}=\square$
Simple interest after 2 year $=\frac{1000 \times 10 \times 2}{100}=\square$
Simple interest after 3 year $=\frac{\square \times \square \times \square}{100}=300$
According to this the simple interest for $4,5,6$ years will be 400, $\square$ $\square$ respectively.
From this $d =$ $\square$ and $a =$ $\square$
Amount of simple interest after 20 years
$t_n+a+(n-1) d $
$t_{20}=\square+(20-1) \square $
$t_{20}=\square$
Amount of simple interest after 20 years is $=$ $\square$
A person is standing at a distance of 80m from a church looking at its top. The angle of elevation is of 45°. Find the height of the church.
A point $P$ is at a distance of $29\ cm$ from the center of a circle of radius $20\ cm$. Find the length of the tangent drawn from $P$ to the circle.
A child makes a poster on a chart paper drawing a square ABCD of side 14cm. She draws four circles with centre A, B, C and D in which she suggests different ways to save energy. The circles are drawn in such a way that each circle touches externally two of the three remaining circles (in the following figure). In the shaded region she write a message 'Save Energy'. Find the perimeter and area of the shaded region.$\Big(\text{Use }\pi=\frac{22}{7}\Big)$
Show that the points (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus. Find the area of this rhombus.
Find the sum of all natural numbers between $1$ and $100$, which are divisible by $3$.
E is a point on side CB, C-B-E, In $\triangle A B C$ AB = AC. If seg AD BC, B-D-C and seg EF $\perp$ side AC, A-F-C. Prove that $\triangle ABD \sim \triangle ECF$. 
Image
The slant height of the frustum of a cone is $4\ cm$ and the perimeters of its circular ends are $18\ cm$ and $6\ cm$. Find the curved surface of the frustum.