Question
Solve the following equations. Check your result in case. $3x + 2(x + 2) = 20 - (2x - 5)$

Answer

$3x + 2(x + 2) = 20 - (2x - 5)$
$\Rightarrow 3x + 2x + 4 = 20 - 2x + 5$
$\Rightarrow 5x + 4 = 25 - 2x$
$\Rightarrow 5x + 2x = 25 - 4 ($By transposing$)$
$\Rightarrow 7x = 21$
$\Rightarrow x = 3$
Check: $L.H.S.= 3x + [2(x + 2)]$
$= 3 \times 3 + 2(3 + 2)$
$= 9 + 2 \times 5 = 9 + 10$
$= 19$
$R.H.S. = 20 - (2x - 5)$
$= 20 - (2 \times 3 - 5)$
$= 20 - (6 - 5) = 20 - 1$
$= 19$
$L.H.S. = R.H.S.$
Hence $x = 3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free