Solve the following equations for x: 4^ 2x =1 32 - Vidyadip

Question

Solve the following equations for x: $4^{2\text{x}}=\frac{1}{32}$

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Answer

We have,$=4^{2\text{x}}=\frac{1}{32}$
$=2^{4\text{x}}=\frac{1}{2}^5$
$=2^{4\text{x}}=2^{-5}$
$=4\text{x}=-5$
$=\text{x}=-\frac{5}{4}$

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