Solve the following equations for x: 4^ 2x =1 32 - Vidyadip

Question

Solve the following equations for x:
$4^{2\text{x}}=\frac{1}{32}$

✓

Answer

We have,

$=4^{2\text{x}}=\frac{1}{32}$

$=2^{4\text{x}}=\frac{1}{2}^5$

$=2^{4\text{x}}=2^{-5}$

$=4\text{x}=-5$

$=\text{x}=-\frac{5}{4}$

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